Now you can write \n to send an actual \n instead of a new line in the POST data.

OpenBullet/OpenBullet.csproj

@@ -547,7 +547,7 @@
       <SubType>Designer</SubType>
       <Generator>MSBuild:Compile</Generator>
     </Page>
-    <Page Include="Pages\Main\Runner\Runner.xaml">
+    <Page Include="Pages\Main\Settings\OB\Runner\Runner.xaml">
       <SubType>Designer</SubType>
       <Generator>MSBuild:Compile</Generator>
     </Page>
@@ -559,7 +559,7 @@
       <DependentUpon>App.xaml</DependentUpon>
       <SubType>Code</SubType>
     </Compile>
-    <Compile Include="Pages\Main\Runner\Runner.xaml.cs">
+    <Compile Include="Pages\Main\Settings\OB\Runner\Runner.xaml.cs">
       <DependentUpon>Runner.xaml</DependentUpon>
     </Compile>
     <Compile Include="MainWindow.xaml.cs">

RuriLib/Blocks/BlockRequest.cs

@@ -6,6 +6,7 @@ using System.Collections.ObjectModel;
 using System.IO;
 using System.Linq;
 using System.Text;
+using System.Text.RegularExpressions;
 using System.Windows.Media;
 
 namespace RuriLib
@@ -401,9 +402,8 @@ namespace RuriLib
             switch (requestType)
             {
                 case RequestType.Standard:
-                    var pData = string.Join(Environment.NewLine, postData
-                        .Split(new string[] { "\\n" }, StringSplitOptions.None)
-                        .Select(p => ReplaceValues(p, data)));
+                    var pData = ReplaceValues(Regex.Replace(postData, @"(?<!\\)\\n", Environment.NewLine).Replace(@"\\n", @"\n"), data);
+
                     if (CanContainBody(method))
                     {
                         if (encodeContent)